One method for separating polypeptides utilizes their different solubilities. the solubility of large polypeptides in water depends upon the relative polarity of their r groups, particularly the number of ionized groups. the more ionized groups there are, the more soluble the polypeptide. which polypeptide, (gly)20 or (lys−ala)3 , is more soluble at ph 7.0 ? (gly)20 (lys−ala)3 which polypeptide, (glu)20 or (phe−met)3 , is more soluble at ph 7.0 ? (phe−met)3 (glu)20 which polypeptide, (ala−asp−gly)5 or (asn−ser−his)5 , is more soluble at ph 3.0 ? (asn−ser−his)5 (ala−asp−gly)5 which polypeptide, (ala−ser−gly)5 or (asn−ser−his)5 , is more soluble at ph 6.0 ? (ala−ser−gly)5 (asn−ser−his)5

the dissolution of polymer can be thermodynamically described in 2 steps.

c. is the answer

by love gaming

catya that's not even a b or c

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2