Asample of water is heated by 520 cal in the temperature rises by 10 k what is the mass of the water sample in grams?

52 g water

In this question we are given;

Amount of heat, Q = 520 calories

Change in temperature, K = 10 K

We are required to calculate the mass of water.

Amount of heat is calculated by multiplying mass by specific heat capacity by change in temperature.

Q = m × c × Δt

The specific heat capacity,c of water = 1 Cal/g°C or 4.184 J/g°C

Rearranging the formula;

m = Q ÷ cΔt

   = 520 Cal ÷ (1 Cal/g°C×10 K)

   = 52 g

Thus, the mass of water sample is 52 g

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o