Compare the solubility of a fatty acid and a fatty acid salt in water. compare the solubility of a fatty acid and a fatty acid salt in water. the salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid. the fatty acid is more soluble in water since it can form stronger hydrogen bonding interactions not available to the fatty acid salt. the salt is more soluble in water since it can form stronger hydrogen bonding interactions not available to the fatty acid. the fatty acid is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid salt.

The correct option is A. The salt is more soluble in water since it can form stronger ion-dipole interactions not available to the fatty acid.

Explanation:

An ion-dipole interaction occurs when an ionic compound is placed in a polar solvent. As salts are ionic compounds and water is a polar solvent, so the fatty acid salts will be able to form electrostatic ion-dipole interactions with the polar water molecules. These interactions will cause fatty acid salts to dissolve in water.

The fatty acid is not an ionic compound and will not form the ion-dipole interactions with the water molecules. Hence, fatty acids will be less soluble in water.

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

your answer is a. the enthalpy of formation for a pure element in its standard state is always positive.