You wish to prepare 50.00 ml of 0.0350 m nh3 from concentrated ammonia (15.28 m) by serial dilution using a 50 ml volumetric flasks, a 1.00 ml volumetric pipet, and a 10.00 ml graduated pipet. for the first dilution in the series, 1 ml of concentrated ammonia is added to a 50.00 volumetric flask and then filled to the line. the solution is mixed thoroughly, poured into a beaker, and then used to make the second solution in the series. what volume of the first solution should be used to make the second solution, 50.00 ml of 0.0350 m nh3 solution, using the glassware provided?

The volume of ammonia required from first solution to make second solution is 5.72 mL

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

       .......(1)

where,

are the molarity and volume of the concentrated ammonia solution

are the molarity and volume of diluted ammonia solution

We are given:

Putting values in equation 1, we get:

Now, calculating the volume of ammonia diluted from first dilution to make the required ammonia solution by using equation 1:

We are given:

= Molarity of ammonia solution from first dilution = 0.3056 M

= Volume of ammonia solution from first dilution = ?

= Molarity of ammonia to make second solution = 0.0350 M

= Volume of ammonia to make second solution = 50.00 mL

Putting values in equation 1, we get:

Hence, the volume of ammonia required from first solution to make second solution is 5.72 mL

passing a magnet thought the

mixture , because iron gets attracted to magnet .

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.