What is the number of grams of cl2 formed when 0.485 mole hcl reacts with an excess of o2

Mass of Cl₂ =  17.25 g

Explanation:

Given data:

Moles of hydrochloric acid = 0.485 mol

Mass of chlorine gas = ?

Chemical equation:

4HCl +  O₂ → 2Cl₂  + 2H₂O

Now we will compare the moles of Cl₂ with HCl .

                  HCl           :               Cl₂

                    4             :               2

                 0.485        :              2/4× 0.485 = 0.243 mol

Oxygen is present in excess that's why mass of chlorine produce depend upon the available amount of HCl.

Mass of Cl₂ :

Mass of Cl₂ = moles × molar mass

Mass of Cl₂ =0.243 mol × 71 g/mol

Mass of Cl₂ =  17.25 g