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Chemistry, 24.10.2019 23:43 ttwright24

N2(g) + 3h2(g) → 2nh3(g) =δh−92.kj in the second step, ammonia and oxygen react to form nitric oxide and water: 4nh3(g) + 5o2(g) → 4no(g) + 6h2o(g) =δh−905.kj calculate the net change in enthalpy for the formation of one mole of nitric oxide from nitrogen, hydrogen and oxygen from these reactions. round your answer to the nearest kj.

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N2(g) + 3h2(g) → 2nh3(g) =δh−92.kj in the second step, ammonia and oxygen react to form nitric oxide...
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