Assume the following substances are soluble in water.

for each of the following fill in the blank with the appropriate whole number.
if a substance dissolves as a molecular unit, enter a value of 0 for the number of ions.

one mole of ammonium carbonate will form moles of ions when dissolved in water.
one mole of methyl alcohol will form moles of ions when dissolved in water.
one mole of methane will form moles of ions when dissolved in water.
one mole of aluminum sulfite will form moles of ions when dissolved in water.
one mole of hydrobromic acid will form moles of ions when dissolved in water

Some substances dissolve in water to yield ions. Molecular substances do not yield ions in solution.

Some substances dissolve in water to yield ions. Solutions of these substances serve as electrolytes. substances such as HBr, (NH4)2CO3, and Al2(SO3)3 all yield ions in solution.

For ammonium carbonate, its dissolution in water occurs as follows;

(NH4)2CO3(s) ⇄ 2NH4^+(aq) + CO3^2-(aq)

Hence three moles of ions are formed when (NH4)2CO3 dissolves in water.

For methyl alcohol and methane, 0 moles of ions will be formed because the compound is molecular and does not form ions.

For aluminum sulfite, its dissolution in water occurs as follows;

Al2(SO3)3(s) ⇄ 2Al^3+(aq) + 3SO3^2-(aq)

We can see that five moles of ions are formed when Al2(SO3)3 is dissolved in water.

For hydrobromic acid, the compound dissolves in water as shown below;

HBr(s) ⇄ H^+(aq) + Br^-(aq)

We can see that two moles of ions are formed when HBr is dissolved in water.

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answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.