What is the molar concentration of fe2+ ion in an aqueous solution if 37.50 ml of 0.118 m kbro3 is required for complete reaction with 11.00 ml of the fe2+ solution? the net ionic equation is: 6fe2+(aq)+bro3−(aq)+6h+(aq)→6fe3+(a q)+br−(aq)+3h2o(l).

2.41 M

Explanation:

6Fe⁺²(aq) + BrO₃⁻(aq) + 6H⁺(aq) → 6Fe³⁺(aq) + Br⁻(aq) + 3H₂O(l)

0.118 M KBrO₃ * 37.50 mL = 4.425 mmol BrO₃⁻

4.425 mmol BrO₃⁻ * = 26.55 mmol Fe²⁺

Thus [Fe²⁺] = 26.55 mmol Fe²⁺ / 11.00 mL = 2.41 M

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