Asolid hydrate weighing 2.682 grams was heated to drive off the water. a solid anhydrous residue remained, which weighed 1.420 grams. calculate the percent of water in the hydrate

47.05%

We are given;

Mass of a solid hydrate = 2.682 grams

Mass of the solid anhydrous residue = 1.420 grams

We are required to determine the percent of water hydrate;

Mass of water = Mass of the solid hydrate - mass of the anhydrous residue

Therefore;

Mass of water = 2.682 g - 1.420 g

                       = 1.262 g

% water in the hydrate = (mass of water ÷ mass of the solid hydrate)×100%

Therefore;

% water in the hydrate = (1.262 g ÷ 2.682 g) × 100%

                                      = 47.05%

Hence, the percent water in the hydrate is 47.05%

i just calculated it all out, and not including weekends, and all the different days off. as of this school year (2018-2019) students are spending 2198 hours in school this year

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.