Asample of seaweed contains two liters of water and has 100 grams of salt dissolved in its cells. the seaweed is placed in a bucket with 4 liters of water and 300 grams of dissolved salt. what will occur when the system reaches equilibrium?

The seaweed will lose 0.5 L of water.

Explanation:

We can calculate the concentration of salt dissolvied in the sample of seaweed:

We can also calculate the salt concentration in the bucket:

Once the seaweed is placed in the bucket, it will act as a semipermeable membrane, allowing an osmosis process, in which water will move from the seaweed (the region with lower concentration) to the bucket (the region with higher concentration). So the seaweed will lose water until the salt concentration the seaweed and the bucket is the same.

It's possible to calculate how much water is transfered:

Because the concentrations are equal:

Now we solve for x:

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.

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