Using your knowledge of thermochemistry, what equation is appropriate to calculate the heat produced from the hcl-naoh reaction?

Neutralization equation:

HCl + NaOH  → NaCl + H₂O + Heat

Heat would calculated through,

Q = m . c. ΔT

Explanation:

When aqueous sodium hydroxide and hydrochloric acid react with each other a neutralization reaction occur. It produces water and salt. The salt would be sodium chloride.

Chemical equation:

HCl + NaOH  → NaCl + H₂O + Heat

The heat produces can be calculated through the given formula.

Q = m . c. ΔT

Q = amount of heat produces

m = total mass of solution

ΔT = change in temperature of solution

C = specific heat capacity of solution

As the mostly solutions are water so we take the specific heat capacity of water which is 4.186 j/g .°C

you need to have a picture of the atom that way we can answer it

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally