Section: 6.2
22) in the reaction shown, what is the mole ratio that would be used to determine the number of
moles of h2 that would be produced when 3.5 moles of aici3 are produced?
3.smols ali1 c1: 3
2 al + 6 hcl → 2 aici3 + 3 h2
a1 26.98 el 35.45
a) 2 moles a
3 moles hc1
2 moles aic 13
b) 3 moles h2
3.5 moles aic 13
c) 3 moles h2
3 moles h2
d) 2 moles aic 13

Exothermic,  physical change after it is already baked

Wyyeurudydudyeye2y3y3y3ueuudisusuisus7w7uwh2u

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.