The rotten smell of a decaying animal carcass is partially due to a nitrogen-containing compound called putrescine. elemental analysis of putrescine indicates that it consists of 54.50% c, 13.73% h, and 31.77% n. calculate the empirical formula of putrescine. (hint: begin by assuming a 100-g sample and determining the mass of each element in that 100-g sample.)

C2H6N

Explanation:

Putrescine formula is C4H12N2

Assuming 100g sample is present

The percent changes to grams and it is converted to moles by dividing it with the atomic masses.

C= 54.50g/12 = 4.541moles

H = 13.73g/1 = 13.73moles

N= 31.77g/14 = 2.269moles

Divide through with the smallest moles value.

C= 4.541/2.269 = 2

H= 13.73/2.269=6

N= 2.269/2.269=1

Therefore the empirical formula is

C2H6N

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally