Using vsper theory, what are the approximate bond angles of a compound that has the central atom with all three electron pairs shared and no lone pair electrons?

a. the molecule will form 109.5o bond angles because the lack of lone pair electrons means there will be no additional repulsion forces acting upon the atoms. therefore, atoms will lie on a trigonal plane.

b. the molecule will form 120o bond angles because the lack of lone pair electrons means there will be no additional repulsion forces acting upon the atoms. therefore, atoms will lie on a trigonal plane.

c. the molecule will form 180o bond angles because the lack of lone pair electrons means there will be no additional repulsion forces acting upon the atoms. therefore, atoms will lie on a linear plane.

d. the molecule will form 105o bond angles because the lack of lone pair electrons means there will be no additional repulsion forces acting upon the atoms. therefore, atoms will lie on a linear plane.

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

water at room temperature is flowing through a pipe with pressure taps located 10 ft apart along one section of the pipe, which are connected to a mercury (s=13.6) manometer.

the answer is a for sure mark brainliest i had got this right on usatestprep