If 9.71 ml of 0.252 koh is used to complete titrate 15.0 ml of hcl , how many moles of hcl are in the solution ?

0.00245 moles of HCl

Explanation:

We are given;

Volume of KOH = 9.71 mL

Molarity of KOH = 0.252 M

Volume of HCl = 15.0 mL

We are required to determine the number of moles of HCl  

Step 1: Write the balanced equation for the reaction

The reaction between HCl and KOH is given by;

KOH(aq) + HCl(aq) → KCl(aq) + H₂O(l)

Step 2: Calculating the number of moles of KOH

Molarity = Moles ÷ Volume

Rearranging the formula;

Moles = Molarity × Volume

          = 0.252 M × 0.00971 L

          = 0.00245 moles

Step 3: Moles of HCl

From the equation, 1 mole of KOH reacts with 1 mole of HCl

Therefore, the mole ratio of KOH : HCl is 1 : 1

Thus,

Moles of HCl will be 0.00245 moles

Therefore, there are 0.00245 moles of HCl in the solution.

The real answer is keeping the world healthy so we won’t die

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.