Ammonia (nh3) ionizes according to the following reaction: nh3(aq) + h2o(l) ⇌ nh4+(aq) + oh–(aq) the base dissociation constant for ammonia (nh3) is kb = 1.8 × 10–5. ammonia (nh3) also has a chloride salt, ammonium chloride (nh4cl), which is soluble in water. if 0.070 m of ammonia (nh3) and 0.035 m of its salt ammonium chloride (nh4cl) are mixed in a solution, what is the ph of this solution?

pH = 9.6

Explanation:

According to Brönsted-Lowry theory, NH₃ is a base and NH₄⁺ its conjugate acid. When they are together in a solution, the form a buffer, which is used to resist abrupt changes in pH when an acid or a base is added. pOH fro a buffer can be found using Henderson-Hasselbalch equation.

Since NH₄Cl is a strong electrolyte, [NH₄Cl] = [NH₄⁺]

Now, we can find pH using the following expression:

pH + pOH = 14

pH = 14 - pOH = 14 - 4.4 = 9.6

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