The hydrolysis of pyrophosphate can be described by the reaction h2po2 7 +h2o ! 2h2po 4 if the ph is held constant, the reaction is pseudo-first order with respect to h2po2– 7 . 126 (a) if, at a given ph, the half-life of pyrophosphate is 140 h at 75c and 13 h at 100c, what is ear for the reaction? (b) estimate the time required for 50% hydrolysis of pyrophosphate in a solution at the same ph as in part (a), but at 20c.

Explanation:

Relation between half-life and rate constant is as follows.

       Half life

Hence, calculate the rate constant as follows.

               k =

                   = 0.00495

Hence, rate constant at is 0.00495 .

Now, at , value of rate constant will be as follows.

            k =

              = 0.0533

Hence, calculate the activation energy as follows.

            = 102.6 kJ/mol

Therefore, value of activation energy is  102.6 kJ/mol .

Now, k at ,

Calculate the time as follows.

           kt =

                   t = 108985 hours

Thus, we can conclude that time required for 50% hydrolysis of pyrophosphate is 108985 hours.

answer: h+ its less than oh

explanation: