When heated, lanthanum(iii) oxalate decomposes as follows: la2(c2o4)3(s) < ===> la2o3(s) + 3 co2(g) + 3 co(g) starting with just the oxalate in a 10.0 l flask, at equilibrium the total pressure observed is 0.200 atm. what is the value of kp for the equilibrium? (dalton’s law of partial pressure! )
Answers: 1
for the equilibrium is 
and 
.
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When heated, lanthanum(iii) oxalate decomposes as follows: la2(c2o4)3(s) < ===> la2o3(s) + 3...
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