011 1.0 points what energy change is associated with the reaction to obtain one mole of h2 from one wang (ew22622) – 19d thermodynamics: first law – ozuna – (92127) 3 mole of water vapor? the balanced equation is 2 h2o(g) → 2 h2(g) + o2(g) and the relevant bond energies are h h : 436 kj/mol; h o : 467 kj/mol; o o : 146 kj/mol; o o : 498 kj/mol. 1. −436 kj 2. +249 kj 3. −425 kj 4. +425 kj

249 kJ

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = 249 kJ

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Answer

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jufsanabriasa

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249 kJ

Explanation:

To obtain the energy change of the reaction:

H₂O → H₂ + ¹/₂ O₂

It is necessary to obtain the difference between bond energy of the products and bond energy of the reactant, thus:

Energy of products:

1 mol of H-H bond × 436 kJ/mol = 436 kJ

¹/₂ mol of O=O bond × 498 kJ/mol = 249 kJ

Energy of reactant:

2 mol of H-O bond × 467 kJ/mol = 934 kJ

Energy change of the reaction is:

934 kJ - (436 kJ + 249 kJ) = 249 kJ

Explanation:

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots