Determine the molar mass of a gas that has a density of 2.18g / l at 67 degrees * c and 720 mm hg

M = 64.1 g/mol

Explanation:

Given data:

Density of gas = 2.18 g/L

Temperature = 67 °C

Pressure = 720 mmHg

Molar mass =?

Solution:

We will convert the mmHg to atm.

720/ 760 = 0.95 atm

Temperature from  °C to K.

67 + 273 = 340 K

Formula:

PM = dRT

M = dRT / P

M = 2.18 g/L ×0.0821 atm. L . mol⁻¹ . K¹ × 340 k / 0.95 atm

M = 60.9 atm. g/mol /0.95 atm

M = 64.1 g/mol

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