Calculate the pressure in the atmosphere of 2.00 moles of helium gas in a 10.0 l container at 27 c

The pressure is 4.926 atm

Explanation:

Step 1: Data given

Number of moles = 2.00 moles

Volume of the gas = 10.0 L

Temperature = 27 °C = 273 + 27 = 300 Kelvin

Step 2: Calculate the pressure

P*V = n*R*T

with P= TO BE DETERMINED

with V = 10.0 L

with n = 2.00 moles

with R = 0.00821 L*atm/ K*mol

T = 300 Kelvin

P = (n*R*T) / V = (2 * 0.00821 * 300) / 10 L = 4.926 atm

The pressure is 4.926 atm

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