If 4.95g of ethane (c2ha) are combusted with 3.25g of oxygen, what is the limiting reagent?
c2h4 + 302
2002 + 2h20

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

The size is 8inches if ur a girl

Electrons are emitted

Ibelieve the answer 4 moles