What is the net ionic equation for the reaction that is represented by the following total ionic equation?
6na+ +2p03- +3ca2+ +601-—> 6na+ +6c1-+ca3(po4)2
2na3po4+3cacl2— > 6naci+ca3(po4)2
2p03- +3ca2+ —> caz(po a)2
2po2- +3ca2++601 6nat+ca3(po4)2
2p5++802- +3ca2+—> caz(po4)2

2PO³^-4(aq) + 3Ca²^+(aq) Ca3(PO4)2(s)

Explanation:

To determine the net ionic equations we need to write the overall balanced chemical equation.

2Na3PO4(aq) + 2Cacl2(aq) 6Nacl(aq) + Ca3(PO4)2(s)

Next is to determine the solubilities of the reactants and products. The solubility rules tells us which products are soluble or not. For this case, the balanced chemical equation gave us the states of the chemical species involved. Therefore, it is expected to precipitate of Calcium Phosphate to form.

The first step in determining the net ionic equation is to write the complete ionic equation. We write the complete ionic equation from each soluble compound as shown below:

6Na+(aq) + 2PO³^-4 + 3Ca2+(aq) + 6Cl-(aq) + 6Na+(aq) + 6Cl-(aq) + Ca3(PO4)2(s)

The net ionic equation only shows the ions that are directly involved inthe precipitation reaction. The net ionic equation does not include the spectator ions which remain dissolved in solution. The net ionic equation is given below:

2PO³^-4(aq) + 3Ca²^+(aq) Ca3(PO4)2(s)

lesson 5 neutralization reactions

1.b

2.d

3.a

4.d

5.c

6.a

7.b

8.a

Explanation:

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