Asolution of 0.207 m aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0690 m naoh . the pka values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-carboxylic acid group, the β-carboxylic acid group, and the amino group, respectively. calculate the ph at the first equivalence point of this titration.

pH = 6,951

Explanation:

The neutral form of aspartic acid is in its isolectric point. For aspartic acid the isoelectric point is the average of pka1 and pka2, thus:

= 2,945

The addition of stoichiometric amounts of NaOH at the first equivalence point will increase the pH at average of pka2 and pka3 thus:

= 6,951

Thus, pH at the first equivalence point is 6,951

I hope it helps!

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.