Gasoline is a mixture of hydrocarbons, a major component of which is octane, ch3ch2ch2ch2ch2ch2ch2ch3. octane has a vapor pressure of 13.95 torr at 25∘c and a vapor pressure of 144.78 torr at 75∘c. use these data and the equation in part (a) to calculate the heat of vaporization of octane.

Explanation:

The expression for Clausius-Clapeyron Equation is shown below as:

Where,  

P is the vapor pressure

ΔHvap  is the Enthalpy of Vaporization

R is the gas constant (8.314×10⁻³ kJ /mol K)

c is the constant.

For two situations and phases, the equation becomes:

Given:

= 13.95 torr

= 144.78 torr

= 25°C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (25 + 273.15) K = 298.15 K

= 298.15 K

= 75°C  = 348.15 K

So,

it takes on an electronical energy

since electrons are negative the answer is neagtaive