Asolution contains 0.021 m cl and 0.017 m i. a solution containing copper (i) ions is added to selectively precipitate one of the ions. at what concentration of copper (i) ion will a precipitate begin to form? what is the identity of the precipitate? ksp(cucl) = 1.0 × 10-6, ksp(cui) = 5.1 × 10-12.

Copper (I) iodide will precipitate first.

Explanation:

We are given:

of CuCl =

of CuI =

Concentration of

Concentration of

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

Putting values in above equation, we get:

Concentration of copper (I) ion =

Putting values in above equation, we get:

Concentration of copper (I) ion =

For the precipitation of copper (I) ions, we need less concentration of copper (I) ions. So, copper (I) iodide will precipitate first.

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