Chemistry, 07.11.2019 02:31 whitwelllife
Pyridinium is a weak acid having a pka of 5.2. how much pyridine (the conjugate base of pyridinium) must be added to an aqueous solution of 0.100m pyridinium (assume the solution volume is constant) to make a buffer that is designed to keep the ph at 4.7?
Answers: 2
![pH=pK_a+log\frac{[Conjugate\ base]}{[weak\ acid]}](/tpl/images/0363/0377/c0611.png)
![pH=pK_a+log\frac{[Py]}{PyH^+]}](/tpl/images/0363/0377/17718.png)
(Pyridinium)=0.100 M![pH=pK_a+log\frac{[Py]}{PyH^+]}\\4.7=5.2 log\frac{[Py]}{0.100}](/tpl/images/0363/0377/de0ef.png)
![4.7-5.2=log\frac{[Py]}{0.100} \\-0.5=log\frac{[Py]}{0.100}\\\frac{[Py]}{0.100}=antilog -0.5\\\frac{[Py]}{0.100}=0.316](/tpl/images/0363/0377/5a83b.png)
![\frac{[Py]}{0.100} =0.316](/tpl/images/0363/0377/cf365.png)
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Pyridinium is a weak acid having a pka of 5.2. how much pyridine (the conjugate base of pyridinium)...
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