Ether, (c2h5)2o, which was originally used as an anesthetic but has been replaced by safer and more effective medications, is prepared by the reaction of ethanol with sulfuric acid. what is the percent yield of ether if 1.17 l (d = 0.7134 g/ml) is isolated from the reaction of 1.500 l of c2h5oh (d = 0.7894 g/ml)? 2 c2h5oh + h2so4 → (c2h5)2o + h2so4 · h2o

87.64% is the percent yield of ether.

Explanation:

Volume of an ether,v= 1.17 L = 1170 mL

Experimental mass of an ether = m

Density of an ether ,d= 0.7134 g/mL

Experimental yield of an ether = 834.678 g

Volume of an alcohol = V = 1.500 L = 1500 mL

Mass of an alcohol = M

Density of an alcohol ,D= 0.7894 g/mL

Moles of an alcohol =

According to recatiopn 2 moles of an alcohol gives 1 mole of an ether.

Then 25.74 moles of alcohol will give:

of an ether.

Mass of 12.87 moles of an ether = 12.87 mol  =74 g/mol = 952.38 g

Theoretical yield of the an ether = 952.38 g

87.64% is the percent yield of ether.

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