005
10.0 points
the molar mass of boron atoms in a natural
sample is 10.76 g/mol. the sample is known
to consist of "b (molar mass 10.013 g/mol)
and b (molar mass 11.093 g/mol). what is
the percentage abundance of 10b?

30.8% B¹⁰

Explanation:

Given data:

Molar mass of boron = 10.76 g/mol

Molar mass of B¹⁰ = 10.013 g/mol

Molar mass of B¹¹ = 11.093 g/mol

Percentage abundance of  B¹⁰ = ?

Solution:

B¹⁰ = x

B¹¹ = 1-x

The equation is,

B¹⁰x + B¹¹(1-x)  = 10.76

10.013 x + 11.093  (1-x) = 10.76

10.013 x + 11.093 - 11.093 x = 10.76

10.013 x  - 11.093 x =  10.76  - 11.093

-1.08 x = -0.333

x = -0.333/-1.08

x = 0.308

0.308 ×100 = 30.8%

30.8% B¹⁰

100-30.8 = 69.2 %

69.2 % B¹¹

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i