Write a structural formula for the principal organic product formed in the reaction of methyl bromide with naoh (sodium hydroxide). click the "draw structure" button to launch the drawing utility. write a structural formula for the principal organic product formed in the reaction of methyl bromide with naoh (sodium hydroxide). click the "draw structure" button to launch the drawing utility.

Methanol is produced as product of the reaction.

Explanation:

Methyl bromide contains a good leaving group because of high polarizability of Br atom and weak C-Br bond.

is a strong base as well as strong nucleophile due to small size and high electronegativity of oxygen atom.

Here methyl bromide primarily acts as an electrophile instead of an acid because of it's very weak acidity.

So, acts as nucleophile towards methyl bromide by replacing bromide ion and forms methanol.

Reaction goes through mechanism.

Structure formula of product has been given below.

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2