If the total pressure of water vapor and hydrogen gas is 1.02 atm and the partial pressure of the water at 22.0 c is 0.13 atm, what is the pressure of the hydrogen gas?

0.89 atm  is the pressure of the hydrogen gas

Explanation:

We can use the molar fractions to solve this

Sum of molar fractions (hydrogen + water vapor) = 1

Molar fraction = Pressure gas / Total pressure

Molar fraction water vapor = 0.13 atm/1.02 atm = 0.127

1 - 0.127 = 0.873 (Molar fraction H2)

0.873 = Pressure H2 / Total pressure

0.873 = Pressure H2 / 1.02 atm

0.873 . 1.02atm = 0.89 atm

answer; i do believe the correct answer is (river); /// good luck

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"