A1.678 g sample of a component of the light petroleum distillate called naphtha is found to yield 5.143 g co2 (g) and 2.456 g h2o (l) on complete combustion. this particular compound is also found to be an alkane with one methyl group attached to a longer carbon chain and to have a molecular formula twice its empirical formula. the compound also has the following properties: melting point of -154 c , boiling point of 60.3 c , density of 0.6532 g/ml at 20 c , specific heat of 2.25 j/(g*c), and -204.6 kj/mol use the masses of carbon dioxide, co2, and water, h2o , to determine the empirical formula of the alkane component. express your answer as a chemical formula?

Explanation:

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At first, based on the given information, one proceeds to compute the moles of carbon that the alkane has by considering the yielded amount of carbon dioxide as follows:

Next, the moles of hydrogen coming from the yielded water as:

Now, dividing by the carbon's moles, one computes the empirical formula as follows:

The closest whole-numbered factor, by multiplying by 3 is:

So it is its empirical formula which allows us to determine the molecular formula if needed which is:

As it is twice the empirical formula.

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explanation:

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