Question 6 (3 points)
click on the link sample calculation type 2 if you need with solving the
problem below.
use the balanced equation to calculate how many ml of a 0.26 m koh solution will
be needed to completely react witn 19.76 ml of 0.20 m h2so4. report your answer
with correct number of significant figures.
h2so4(aq) + 2koh(aq) - k2so4(aq) + h2o(1)
your
answer

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied