2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) t
he δhf for fe2o3(s) = -824.3 kj/mole.
the δhf for al2o3(s) = -1675.7 kj/mole.
finish the equation.
δhrxn = [(1) ( kj/mole) + (2) ( kj/mole)] - [(1) ( kj/mole) + (2) ( kj/mole)]

ΔHrxn = [(1) -1675.5 ( kJ/mole) + (2) 0 ( kJ/mole)] - [(1) -824.3 ( kJ/mole) + (2) 0 ( kJ/mole)]

Explanation:

ΔHrxn = 2ΔHf (Al₂O₃)  - ΔHf (Fe₂O₃)

Remember that for pure elements in their standard state of temperature and pressure by definition their standard heats of formation are zero.

ΔHrxn = 2(-1675.7) - (-824.3) kJ/mol

ΔHrxn = 2527 kJ/mol

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

the answer is   c.) 1575 j.

explanation: