Place the following in order of increasing f-a-f bond angle, where a represents the central atom in each molecule. pf3 of2 pf4+ group of answer choices pf3 < of2 < pf4+ of2 < pf3 < pf4+ pf4+ < of2 < pf3 pf4+ < pf3 < of2 of2 < pf4+ < pf3 pf3 < pf4+ < of2

PF4+ < PF3 < OF2

Explanation:

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In this case, the two non-shared pairs of electrons present on the OF2 occupy more space and causes the FOF bond angle to be the largest one (180°) due to its planar arrangement. Furthermore, PF3 has just 1 non-shared pair of electrons, therefore there is less space for the bonds to be trigonally arranged, it means, a smaller angle (120°). Finally, PF4+ shows a perfectly tetrahedral arrangement therefore it has the smallest bond angle (109.5°).

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law of conservation of matter