A10.0 ml sample of 0.75 m ch3ch2cooh(aq) is titrated with 0.30 m naoh(aq) (adding naoh to ch3ch2cooh). determine which region on the titration curve the mixture produced is in, and the ph of the mixture at each volume of added base. ka of ch3ch2cooh is 1.3× 10−5. henderson–hasselbalch equation: latex: ph

the answer to your question is c.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally