5. the temperature of a piece of metal whose mass is 1200 g increases from 10.0°c to
20.0°c when it absorbs 3440 j of heat energy. what is the specific heat of the metal?

Specific heat capacity of metal is 0.29 j/g.°C.

Explanation:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Given data:

Mass of metal = 1200 g

Initial temperature = 10 °C

Final temperature = 20 °C

Heat absorbed = 3440 j

Specific heat of metal = ?

Solution:

ΔT  = 20 - 10 = 10 °C

Q = m.c. ΔT

c = Q / m.ΔT

c = 3440 j / 1200 g×10 °C

c = 3440 j / 12000 g.°C

c = 0.29 j/g.°C

so what is the problem with your lab report and whats the subject of the lab report? i will you

answer; capital earns interest; entrepreneurship receives a profit or incurs a loss;