Select the correct answer.
a mixture consists of glucose and water. what is the percent composition of glucose in the mixture if it contains 1.3 moles of glucose (c6h1206)
and the total mass of the mixture is 276 grams?

% composition of glucose =  85 %

Explanation:

Given Data

moles of glucose (C₆H₁₂O₆) = 1.3 mole

Total mass of mixture = 276 g

percent composition of glucose (C₆H₁₂O₆) = ?

Solution

Number of moles are given so we find out the mass of C₆H₁₂O₆

mass = moles × molar mass

Molar mass of glucose = 180.156 g/mol

mass = 1.3 mol × 180.156 g/mol

mass = 234.2 g

Now we find out the percent composition of glucose

% composition =  (mass of compound ÷ mass of mixture) × 100

% composition =  ( 234.2 g ÷ 276 g) × 100

% composition =  0.85 × 100

% composition =  85 %

the potential energy of the reactants is 200j.

from the energy diagram, the energy of the product formed is 350j; this means that, this reaction is an endothermic reaction, because it absorbs energy from its environment.

the answer is 75.0%.