H2a and boh are acid and base and they react according to the following balanced equation: h2a(aq) + 2 boh(aq) → b2a(aq) + 2 h2o(l) if 0.20 moles of boh reacted with excess amount of h2a solution and 1500. j of heat was released by the reaction, what is the ∆hrxn for the reaction as written above?

ΔH=15000 J  =  15KJ

Explanation:

In this exercise  you have find the enthalpy of reaction this is the difference between enthalpy of reactans and products,

For the following equation

H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O(l)

We know that 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J

so,

(2mol/0,2mol)*1500J=15000J

for de reactions exothermics tha enthalpy is negative so:

ΔH=15000 J  =  15KJ

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.