How many moles of mgcl2 are there in 342 g of the compound?

There are  342 g/ 95. 2 g/m = 3.59 moles

Explanation:

MgCl2 → Molar mass is 95.2g g/m

This is the mass in one mol so to find out the moles in 342g we have to divide the mass between the molar mass.

342 g/ 95. 2 g/m = 3.59 moles

3.6 moles of are present in 342 g of

Explanation:

Given the weight of compound  = 342 g

Atomic Mass of Mg = 24 amu

Atomic Mass of Cl = 35.5 amu

Computing the molar mass of  = amu = 24 + 71 = 95 amu

No. of moles of a compound is calculated by the formula =

Substituting the value,

Moles =

Therefore, 3.6 moles of  are present in 342 g of

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