Rubidium is a soft silvery-white metal that has two common isotopes, 85rb and 87rb. if the abundance of 85rb is 72.2% and the abundance of 87rb is 27.8%, what is the average atomic mass of ribidium?

Average atomic mass of Rb = 85.6 amu.

Explanation:

Abundance of Rb⁸⁵ = 72.2%

Abundance of Rb⁸⁷ = 27.8%

Average atomic mass = ?

Solution:

Average atomic mass of Rb= (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass of Rb = (85×72.2)+(87×27.8) /100

Average atomic mass of Rb =  6137 + 2418.6 / 100

Average atomic mass of Rb = 8555.6 / 100

Average atomic mass of Rb = 85.6 amu.

answer: lol

explanation:

lol

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.