The value of δ°′δg°′ for the conversion of glucose-6-phosphate to fructose-6-phosphate (f6p) is +1.67 kj/mol+1.67 kj/mol . if the concentration of glucose-6-phosphate at equilibrium is 1.85 mm1.85 mm , what is the concentration of fructose-6-phosphate? assume a temperature of 25.0°c25.0°c .

Answer : The concentration of fructose-6-phosphate is 0.275 mM

Explanation :

First we have to calculate the value of equilibrium constant.

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = +1.67 kJ/mol = +1670 J/mol

R = gas constant  = 8.314 J/K.mol

T = temperature  =

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

Now we have to calculate the concentration of fructose-6-phosphate.

The expression of equilibrium constant is:

Therefore, the concentration of fructose-6-phosphate is 0.275 mM

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.