If a 3.6 moles of an ideal gas occupies 150 ml tank at a temperature of -5 °c, what is the pressure inside the tank?

528.086 atm

We are given;

The number of moles of an ideal gas as 3.6 moles

Volume occupied by the gas is 150 mL or 0.15 L

Temperature of the gas is -5° C

But, K = °C + 273.15

Therefore, Temperature, T = 268.15 K

We are required to calculate the pressure in the tank.

In this case we are going to use the ideal gas equation;

P = nRT÷ V

 = (3.6 mole × 0.082057 × 268.15 K)÷ 0.15 L

 =528.086 atm

Therefore, the pressure in the tank is 528.086 atm