Nh4no3, whose heat of solution is 25.7 kj/mol, is one substance that can be used in cold pack. if the goal is to decrease the temperature from 25.0 °c to 5.0 °c, how many grams of nh4no3 should we use for every 100.0 g of water in the cold pack? assume no heat was lost outside of cold pack, and the specific heat of the resulted solution was the same as water, or 4.184 j/(g•°c).
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There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several useful plastics. in the first step, calcium carbide and water react to form acetylene and calcium hydroxide: cac2 (s) + 2h2o (g) → c2h2 (g) + caoh2 (s) =δh−414.kj in the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6c2h2 (g) + 3co2 (g) + 4h2o (g) → 5ch2chco2h (g) =δh132.kj calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions. round your answer to the nearest kj .
Answers: 3
Nh4no3, whose heat of solution is 25.7 kj/mol, is one substance that can be used in cold pack. if th...
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