The density of solid ag is 10.5 g/cm3. how many atoms are present per cubic centimeter of ag?

The molar mass of Ag is 108 grams per mole.

So, divide the density of Ag which is 10.5 g/cm3 by 108 grams per mole and you will get 0.0972 moles per cubic centimeter.

Using Avogadro’s law where 1 mole of substance equals 6.023 x 10^23 atoms

0.0972 moles per cubic centimeter (6.023 x 10^23 atoms/mole) = 5.86 x 10^22 atoms Ag

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

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