Each step in the following process has a yield of 70.0%. ch4+4cl2⟶ccl4+4hcl ccl4+2hf⟶ccl2f2+2hcl the ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol ch4 reacts, what is the total amount of hcl produced? assume that cl2 and hf are present in excess. moles hcl : mol

n(HCl)=1.96 mol

Explanation:

CH4+4Cl2⟶CCl4+4HCl

CCl4+2HF⟶CCl2F2+2HCl

With ideal yields we will end up with 4 moles of HCl.

With 70% yields on every stage

n(HCl)=0.7*0.7*4=1.96 mol

58750.08068 is the answer i think

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.