If the enzyme molecule has more than one active site, then [e]t is multiplied by the number of active sites to determine its effective concentration. determine the value of the turnover number of the enzyme carbonic anhydrase, given that for carbonic anhydrase equals 249 μmol⋅l−1⋅s−1 and [e]t=2.20 nmol⋅l−1 . carbonic anhydrase has a single active site. turnover number =

The value of the turnover number of the enzyme carbonic anhydrase is .

Explanation:

The turnover number is defined as maximum number of conversions of substrate molecules per second by a single catalytic site for given a concentration of enzyme..

Turn over number =

=catalytic site concentration

= Maximum reaction rate

We are given with:

Turnover number :

=

The value of the turnover number of the enzyme carbonic anhydrase is .

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

sry but any answer choices