Assume a scuba diver is working at a depth where the total pressure is 5.0 atm (about 50 m below the surface). what mole fraction of oxygen is necessary in order for the partial pressure of oxygen in the gas mixture the diver breathes to be 0.210 atm?

0.042

Explanation:

The partial pressure of a gas is given by Raoult's law, which is:

where,

= partial pressure of oxygen = 0.210 atm

= total pressure = 5.0 atm

= mole fraction of oxygen = ?

Putting values in above equation, we get:

Hence, the mole fraction of oxygen necessary in order for the partial pressure of oxygen in the gas mixture the diver breathes to be 0.210 atm is 0.042.

the reaction mixture contains some ammonia, plus a lot of unreacted nitrogen and hydrogen. the mixture is cooled and compressed, causing the ammonia gas to condense into a liquid. the liquefied ammonia is separated and removed. the unreacted nitrogen and hydrogen are then recycled back into the reactor .