Describe how copper sulfate crystals are formed from reacting copper oxide+sulfuric > copper sulfate + water

(reward is 25 points)

1. Follow all safety instructions.

Objective/Aim: Dilute sulfuric acid and copper(ii)oxide powder to produce copper(ii)sulphate. At the end of the experiment, blue copper(ii) sulfate pentahydrate crystals should be obtained.

Steps/procedures:

1. Place some sulfuric acid in a conical flask and warm it in a water bath. (warm acid is used for a faster reaction with the copper(ii)oxide)

2. Add a spatula of copper oxide powder to the acid and stir with a glass rod.

3. Continue adding copper oxide powder until it is in excess.

4. Filter the mixture to remove the excess copper oxide.

5. Pour the filtrate (the copper sulfate solution) into an evaporating basin.

6. Heat the copper sulfate solution to evaporate half of the water.

7. Pour the solution into a watch glass and leave to allow all of the water to evaporate

Record the appearance of the copper sulfate, including its color and shape.

USE DILUTE SULFURIC ACID!!!

explanation:

i think option no d is the correct answer

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%