Iodine, i2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. what is the temperature (in k) in a 71.4 ml bulb that contains 0.276 g of i2 vapor at a pressure of 0.478 atm?

382.63 K

We are given;

We are required to calculate the temperature of Iodine

T = PV ÷ nR

But, n, the number of moles = Mass ÷ Molar mass

Molar mass of iodine = 253.8089 g/mol

Thus, n = 0.276 g ÷ 253.8089 g/mol

           = 0.001087 moles

Therefore;

T = (0.478 atm × 0.0714 L) ÷ (0.001087 moles × 0.082057)

  = 382.63 K

Thus, the temperature of Iodine in Kelvin is 382.63 K

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.

i believe the answer is three water molecules